[time-nuts] Zeeman Audio Source?
Chuck Harris
cfharris at erols.com
Wed Jan 12 23:49:45 UTC 2005
Hi Brooke,
When I do the math, I get:
P = (1V)^2 / 50 = 20mw
and
P = (5V)^2 / 600 = 42mw
The power is there, so therefore, so is the voltage with the
correct transformer.
Or, another way, remembering that the ratio of the impedances
is the square of the turns ratio:
600/50 = 12:1 impedance, therefore we need a transformer
that has a SQRT(12) : 1 turns ratio, which is about 4:1
-Chuck
Brooke Clarke wrote:
> Hi Chuck:
>
> My first thought was a transformer, but I did the math and don't see how
> it can work.
> An amplifier sure will and that's probably the most inexpensive way.
>
> Have Fun,
>
> Brooke
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