[volt-nuts] ESI SR 1010 question From July 2013

[Joe Hobart]

In July, MK asked about the configuration for the ESI SR 1010 series-parallel
compensation network.  I have not seen a reply, so I measured mine.  A schematic
would be easier, but I will try to describe the connections:

Visualize nine resistors in series in the SR 1010, numbered 1 to 9.

Shorting bar number one connects to the outside end of resistor 1 and the
junction between resistors 6 and 7.

Shorting bar number two connects to the outside end of resistor 9 and the
junction between resistors 3 and 4.

This provides the series-parallel combination between the shorting bars.


One side of the compensation network connects an approximately 0.6 Ohm resistor
to the outside end of resistor 1 and an approximately 0.3 Ohm resistor to the
junction of resistors 6 and 7.  These resistors are connected to the same points
as shorting bar number one.

The other side of the compensation network connects an approximately 0.6 Ohm
resistor to the outside end of resistor 9 and an approximately 0.3 Ohm resistor
to the junction of resistors 3 and 4.  These resistors resistors are connected
to the same points as shorting bar number two.

There, that should be perfectly clear!  The series-parallel compensation network
connects to the SR 1010 at only four points plus ground.

The higher value resistors in the compensation network connect to only one
resistor in the SR 1010 (an outside end); the lower value resistors in the
compensation network connect to junctions of two resistors in the SR 1010.

The parallel compensation network is similar with approximately one Ohm
resistors supplying current to junctions of two resistors and approximately two
Ohm resistors supplying current to single resistors.

Joe