[time-nuts] Help w/integration problem
mfeher at eozinc.com
Mon Jan 2 08:10:39 EST 2006
I wrote a program about 20 years ago to calculate the total integrated noise
power from the individual power spectrum density points. It is in GW Basic
and I still use it almost daily. Let me know if you would like it. 73 - Mike
Mike B. Feher, N4FS
89 Arnold Blvd.
Howell, NJ, 07731
From: time-nuts-bounces at febo.com [mailto:time-nuts-bounces at febo.com] On
Behalf Of John Miles
Sent: Monday, January 02, 2006 3:00 AM
To: Discussion of precise time and frequency measurement
Subject: [time-nuts] Help w/integration problem
Does anyone have a piece of C (BASIC, whatever) code that turns an array of
dBc/Hz values into integrated RMS noise?
I'm trying to use a simple rectangular integrator to divide a log-log plot
for (i=L_column; i < U_column-1; i++)
sum += ((value[i] - ((value[i] - value[i+1]) / 2.0)) *
(frequency[i+1] - frequency[i]));
This just takes the midpoint dBc/Hz value between successive columns of a
phase-noise plot, multiplies it by the frequency step between the columns in
question, and sums the result for all columns in the range of interest.
The output of this process, when I feed a typical noise graph with values
around -110 dBc/Hz to it, with frequency values at the lower and upper
limits of 1000 and 10000 Hz, is around -1E+6. What I'd *like* is a value
corresponding to the "-63 dBc" value cited on pages 7 and 8 in this Zarlink
In this note, the author shows a noise curve similar to the ones I'm working
with, and magically pulls -63 dBc out of the ether with no explanation of
the integration process that obtained it. (What does it mean, in the
author's words, to take the area "under" a phase-noise curve, anyway?
What's the bottom dBc/Hz value?)
Being from the instant-gratification generation, I really don't want (and
won't understand) a calculus lecture. I want the 5 lines of code that do
the integration. :-) This is for the next release of my freeware GPIB
noise-measurement app, so your karma will be integrated along with the noise
if you're able to help!
-- john, KE5FX
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