[time-nuts] Efratom M100 oscillator connector

Robert E. Martinson REMartinson at rcn.com
Tue Dec 25 07:49:08 UTC 2007


A connector on Ebay now, see: 250200168413.

Kind of pricey with no backshell or screws.


Bob  



-----Original Message-----
From: Robert E. Martinson [mailto:REMartinson at rcn.com] 
Sent: Sunday, December 23, 2007 1:34 AM
To: 'Discussion of precise time and frequency measurement'
Subject: RE: [time-nuts] Efratom M100 oscillator connector


HI Mike, 

I have 2 FRK's here, both use a connector made by Positronic, it's a "SGM
20".
See http://www.connectpositronic.com/downloads/pdf/C008RevC_HighDenRec.pdf

The Positronic site (for Australia) is:

Australia (Commercial & Industrial & selected Military Accounts)
Walcom Pty. Ltd
118 Pryor Road
Ourimbah, NSW 2258 Australia
Phone: + 61 2 4362 3477
Fax: + 61 2 4362 3293
www.walcom.com.au
Contact: Mark Walpole
mark at walcom.com.au


I bought one complete, used connector assembly on Ebay a while ago for like
$10.  The P/N on the backshell is stamped "M28748/8-D10L1A".



Regards,
Bob Martinson, N1VQR



-----Original Message-----
From: time-nuts-bounces at febo.com [mailto:time-nuts-bounces at febo.com] On
Behalf Of mlmccauley
Sent: Saturday, December 22, 2007 10:20 PM
To: time-nuts at febo.com
Subject: [time-nuts] Efratom M100 oscillator connector



I got a really good deal on a used Ball Efratom M-100 oscillator, and I 
am unable to find a power connector for it. The manual for the unit 
states that it is a part number

M28748-/8-D10LIA

Evidently the M28748 series of connectors are fairly widely used in 
military equipment, but a search for that particular p/n didn't turn up 
anything, none of the parts houses that I deal with handle mil type 
connectors, and I really doubt of I would have any luck at all as an 
electronics hobbyist calling up a defense contractor trying to buy one 
connector (to say nothing of what they would want for it even if they 
agreed to sell one to me...).

The connector is rectangular and has three rows of pins, seven in the 
two outer rows and six in the center.

Anyone have any ideas?

Thanks in advance,

Mike


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