[time-nuts] Pendulums & Atomic Clocks & Gravity

Brooke Clarke brooke at pacific.net
Sat May 26 16:34:24 EDT 2007


Hi Bill:

It's my understanding that a satellite is in free fall, hence zero g.

Of course there's a gravitational field at the location of the satellite, the 
one from Earth being the largest.  Orbital mechanics gives me a headache so 
let's hear from someone more knowledgeable.

Have Fun,

Brooke Clarke, N6GCE
http://www.PRC68.com
http://www.precisionclock.com



WB6BNQ wrote:
> Brooke Clarke wrote:
> 
> 
>>Gravity also effects atomic clocks, see: http://www.leapsecond.com/great2005/
>>and this puts a limit on what can be done with any atomic clock that's on
>>Earth.  "g" will always have minor fluctuations (noise) due to all sorts of
>>things like the Sun, Moon, planets, asteroids, earthquakes, etc.  It's still a
>>direct "g" effect called red shift like (U2 − U1)/c2, where the Us are
>>gravitational potentials, only smaller by c squared.
> 
> 
> If all of the above affects the gravitational action on the surface of the Earth,
> then how is the statement, below, true ?
> 
> 
>>I expect that in not too many years the official master clocks will no longer
>>be on Earth, but instead in satellites.  There "g" is precisely known to be
>>zero.  Since GPS satellites are excellent for time transfer that's where they
>>will be.  The ensemble will be the full constellation.
> 
> 
> It would seem that the satellite, which is just an arms throw from the surface,
> would have the same affects acting upon it, albeit perhaps in modified ways.  I
> would think the satellite would have to be placed at the center of the SUN to have
> all of the effects (within our solar system) reduced to the smallest amount.
> 
> Can anyone elaborate on this ?  Thanks,
> 
> Bill......WB6BNQ
> 
> 
> 
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