[time-nuts] Pendulums & Atomic Clocks & Gravity
brooke at pacific.net
Sat May 26 16:34:24 EDT 2007
It's my understanding that a satellite is in free fall, hence zero g.
Of course there's a gravitational field at the location of the satellite, the
one from Earth being the largest. Orbital mechanics gives me a headache so
let's hear from someone more knowledgeable.
Brooke Clarke, N6GCE
> Brooke Clarke wrote:
>>Gravity also effects atomic clocks, see: http://www.leapsecond.com/great2005/
>>and this puts a limit on what can be done with any atomic clock that's on
>>Earth. "g" will always have minor fluctuations (noise) due to all sorts of
>>things like the Sun, Moon, planets, asteroids, earthquakes, etc. It's still a
>>direct "g" effect called red shift like (U2 âˆ’ U1)/c2, where the Us are
>>gravitational potentials, only smaller by c squared.
> If all of the above affects the gravitational action on the surface of the Earth,
> then how is the statement, below, true ?
>>I expect that in not too many years the official master clocks will no longer
>>be on Earth, but instead in satellites. There "g" is precisely known to be
>>zero. Since GPS satellites are excellent for time transfer that's where they
>>will be. The ensemble will be the full constellation.
> It would seem that the satellite, which is just an arms throw from the surface,
> would have the same affects acting upon it, albeit perhaps in modified ways. I
> would think the satellite would have to be placed at the center of the SUN to have
> all of the effects (within our solar system) reduced to the smallest amount.
> Can anyone elaborate on this ? Thanks,
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