[time-nuts] Accurate Thunderbolt position

Brooke Clarke brooke at pacific.net
Tue Jul 14 22:55:59 UTC 2009


Hi Mark:

0.00001 degrees (five decimal places) = 0.00060' = 0.0360" of arc.
If one second of arc is about 100 feet of longitude then the total distance for 
0.00001 degrees is about 3.6 feet.  To get latitude multiply by COS(your lat).
That way you know how far to move the antenna.

But to check apply the above to the Z12 antenna, i.e, see if you can move the 
Z12 antenna so it's position, after OPUS, is right on a five digit location.

One of my goals is to locate a number of survey monuments so that they are on 
even arc second locations.  i.e. 123:24:40.00000000, 123:24:50.00000000, etc.
It's an iterative process.

Have Fun,

Brooke Clarke
http://www.prc68.com

Mark Sims wrote:
> Well,  I implemented a test of getting the tbolt to lock in a precise location.  After entering 3D-fix mode,  it would fairly reliably output a location within 1 foot of my surveyed (within 4mm lat/lon) spot within 15 minutes of observations.  
> 
> The problem is when I see the location match,  I issue the command to enter position hold mode...  but the receiver takes 2 seconds to get around to processing that command...  during which time it has done two more fixes... which are no longer within the desired error radius...  craptastic.
> 
> I guess I can just keep repeating the process until the receiver stops within the desired radius...  which could  take quite a while (if ever).
> 
> 
> 
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