[time-nuts] state of the art devide by ten
EWKehren at aol.com
EWKehren at aol.com
Mon Mar 30 11:46:18 UTC 2009
In my opinion the best way is still to use two 74xx90 connected divide by
five and divide by two. That gives a symmetrical output. That is why you can not
use a 390. The A output should subsequently be applied to a D or JK flip
flop with the clock input connected to the 10 MHz. The D or JK F/F should be as
fast as what is presently still available.
Bert Kehren Miami WB5MZJ
In a message dated 3/30/2009 1:10:57 A.M. Eastern Daylight Time,
hmurray at megapathdsl.net writes:
> What would be a "through the hole" type of IC that would have less
> jitter than a 74xx90. I CAN do surface mount if I have to.
In general, I think faster logic families have lower jitter. I'm not sure
I
could prove that or find a good paper. There may be counter-examples.
If you want low jittter, I think the right approach is to divide by X/2 and
then do the final divide by 2 in a separate chip. There are several logic
families that have only one gate or one FF in a package. They are usually
SMT, typically SP-23 type packages with fairly big pins so hand soldering
with old-fart eyes is not that hard.
Prop time with multiple outputs in a package depends on how many outputs are
switching. In the case of a divide by 10, the pattern is stable. If you
look at the divide by 2 output pin, I'd expect more jitter since sometimes
lower order bits are switching and sometimes they are not.
Another approach is to use a CPLD. Clock the main divide by 10 or 100 on
the
wrong edge, and then buffer the final output on the right edge. Some CPLDs
are targeted at low power. It'd expect them to have more jitter than the
ones targeted at high-speed. There may not be much choice.
--
These are my opinions, not necessarily my employer's. I hate spam.
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