[time-nuts] Regulating a pendulum clock
jimlux
jimlux at earthlink.net
Tue Aug 10 01:48:17 UTC 2010
Bruce Griffiths wrote:
> Advisable given the required mass will probably be in the 10-100 ton range.
>
> Bruce
>
> J. L. Trantham, M. D. wrote:
>> Personally, I would get out of the way. : )
>>
>> Joe
>>
Wait a minute.. is it that big? or is it much, much bigger..
Inverse square is involved.
The moon's mass is 7.3E22 kg, and it's 400 km away (eccentric 0.055)
Let's say our mass is 4 meters from the pendulum... that's a factor of
1e5, so the inverse square is 1e10.. 7.3E22 /1e10 = 7.3E12 kg
required... A bit more than 100 tons..<grin>
Call it 7E9 tonnes. If it were water, a sphere about 1200 meters in
radius...
I'm assuming you'll be using something really really dense (depleted
Uranium, perhaps.. very, very inexpensive in 80,000 pound lots) that
will get you about 20 times denser.. get you down to a 400 meter radius
sphere.
Not sounding too practical yet...
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