[time-nuts] 5120A and PM singal

[Azelio Boriani]

Should the peak level be at 10MHz? Why 10KHz? 10KHz is the delta from the
carrier: 10MHz plus or minus 10KHz. Moreover, 1Hz is 2*pi*Rad, 1Rad should
be 1Hz/(2*pi).

On Mon, Jan 14, 2013 at 11:35 AM, Filip Amator <filip.amator at gmail.com>wrote:

> Hello,
>
> I made a simple measurement using Symmetricon 5120A phase noise
> measurement set and a Marconi 2024 signal generator and I don't
> understand the results. I measured the phase noise of 10 MHz signal
> with 1 Rad phase modulation at 10 kHz, and I got from mesurement peak
> at 10 kHz with level about -26dBc/Hz. According to the current
> definition of dBc/Hz, the value of -26dBc/Hz should be considered as a
> -26dB of modulation relative to 1 Rad. But I would expect that the
> peak level will be at 0 dBc at 10 kHz. Does anyone knows how to
> explain this difference?
>
>
> Filip Ozimek
>
> _______________________________________________
> time-nuts mailing list -- time-nuts at febo.com
> To unsubscribe, go to
> https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts
> and follow the instructions there.
>