[time-nuts] Clock level conversion 5V -> 3.3V

Vasco Soares vesoares at deea.isel.ipl.pt
Wed Oct 1 04:47:45 EDT 2014


Hi,

More than a matter of personal taste avoiding a resistive divider using a 
active circuit you could benefit from its low output impedance. With a 
resistive divider there could be some issues in terms of impedance matching 
when a load it is present but as been said it all depends on how good that 
level translation should be.

Regards,
Vasco Soares


----- Original Message ----- 
From: "Hal Murray" <hmurray at megapathdsl.net>
To: "Discussion of precise time and frequency measurement" 
<time-nuts at febo.com>
Cc: <hmurray at megapathdsl.net>
Sent: Wednesday, October 01, 2014 4:10 AM
Subject: Re: [time-nuts] Clock level conversion 5V -> 3.3V


>
> vesoares at deea.isel.ipl.pt said:
>> I would suggest some 3.3V logic (inverter) gate with 5V tolerant inputs
>> from Little Logic TI portfolio. There are buffered and unbuffered gate
>> available.
>
> What's the advantage of a chip over a pair of resistors?
>
> haunma at keteu.org said:
>> I have seen a resistive divider used in a similar application, but 
>> wondered
>> if I could save the couple dozen mA they were spending.
>
> Power might be one.  If it's a long enough run that you need a 
> termination,
> then the power doesn't cost anything extra.  If it's only a few inches, 
> you
> can use higher values of resistance to save the power.
>
> For a given value of resistance and a specific chip, there should be some
> crossover frequency where the power of the chip matches the power of the
> resistors.  It might be fun to play with the numbers.
>
>
>
> -- 
> These are my opinions.  I hate spam.
>
>
>
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