[time-nuts] 10 MHz -> 16 MHz

Jeremy Nichols jn6wfo at gmail.com
Sun Sep 30 04:30:25 UTC 2018


How about three doublers: 10 MHz -> 20 -> 40 -> 80 MHz and then divide
by 5 -> 16 MHz?

Jeremy
N6WFO

On Sat, Sep 29, 2018 at 9:17 PM Hal Murray <hmurray at megapathdsl.net> wrote:
>
>
> > What's a clever, simple, reliable (pick 2 of 3) way to get 16 MHz out of 10
> > MHz? Low phase noise isn't a big requirement and jitter doesn't need to be
> > sub-nanosecond. The main requirement is perfect cycle count accuracy. This is
> > for driving a 16 MHz microcontroller from a 10 MHz Rb/Cs/GPSDO. 10 MHz input
> > is likely sine; 16 MHz output is 3v3 or 5v CMOS.
>
> There should be a PLL chip that includes the M and N dividers, but I'm not
> familiar with that area.
>
> Some/many ARM chips include PLLs so you can use a convenient Xtal and run the
> CPU at a higher speed.  You might look for low cost break out boards for an
> SoC ARM.  Remove their Xtal, feed your 10 MHz into the right pad.  Program it
> to setup one of the counter/timers to do the right divide.
>
>
> --
> These are my opinions.  I hate spam.
>
>
>
>
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