[time-nuts] Phase noise confusion II

[Hal Murray]

richard at karlquist.com said:
> There is always an implied clock recovery loop that the the jitter is
> measured against. The loop may itself affect the jitter measurement either by
> cleaning up jitter or contributing to it. 

Interesting.  I hadn't thought about it that way.

Suppose I measure the edge to edge times and make a histogram.  Can I get 
jitter out of that?  Where is the clock recovery loop?

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