[time-nuts] La Crosse Clocks -
Alex Pummer
alex at pcscons.com
Sun Dec 27 02:19:32 UTC 2020
actually you could transmit and receive on the same frequency if you
take care that they have different polarization. A small transmit loop
around -- vertical axis -- the building and very low power and receive
the wwvb normally with the ferrite roads with horizontal axis, the
transmission outside of the loop is negligible, I am running such a
system for my old clocks, wwvb receiver antenna properly oriented in the
attic, amplifier downstairs, the loop cca 1/2' from the ground an one
LM386 "drives" the loop with low power, just you have to turn you
clock's ferrite - antenna vertically.
73
KJ6UHN
Alex
On 12/26/2020 5:23 PM, Tom Van Baak wrote:
> > Transmitting on the same frequency you are receiving on seems like
> asking for troubles.
>
> Same frequency, but you wouldn't do both at the same time. See, you
> can't transmit AM WWVB until you first know what time it is. To get
> the time you enable the ES100 and listen to BPSK WWVB. So the ES100
> receiver and Arduino transmitter are not active as the same time. One
> example might be to enable the ES100 for 3 minutes each hour and run
> the Arduino for the balance.
>
> > How far apart would the antennas have to be?
>
> Use the standard dual right angle ES100 antenna setup to receive BPSK
> WWVB. For transmit, you likely don't need, and legally don't want, an
> antenna. The Arduino is likely within a few feet of the 24h RC clock
> that you're trying to set. If it doesn't work first time, dangle a
> jumper off the GPIO pin.
>
> /tvb
>
>
> On 12/26/2020 1:59 PM, Hal Murray wrote:
>> tvb at LeapSecond.com said:
>>> Use a ES100 board [2] to receive the real BPSK WWVB and then
>>> generate a fake
>>> AM WWVB signal for the 24h clock to receive. That way you get the
>>> enhanced
>>> reception of the new format and the wide clock selection of the
>> Transmitting on the same frequency you are receiving on seems like
>> asking for
>> troubles.
>>
>> How far apart would the antennas have to be? How would you calculate
>> that
>> distance? Or what is the right question?
>>
>>
>
>
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