[time-nuts] WWVB Dephaser Question

[Bob kb8tq]

Hi

Some of the folks doing this are running pretty massive antennas. 

If you believe that the max signal from WWVB into your antenna 
is around 1 mV and accept the 5V p-p number, then you would need
at least 74 db simply to have it not be equal to the transmit signal 
at max signal levels. You probably want it 20 db below that level 
to have a rational setup. That gets you to 94 db. If you see 20 to 
40 db fades below “max” then you are into the 114 to 134 db range. 

This is not to say you can’t get the job done. Only that you would
need to pay a bit of attention to the issue ….

Bob

> On Oct 8, 2020, at 4:50 PM, rcbuck at atcelectronics.com wrote:
> 
> Bob,
> 
> I am using a ferrite rod antenna for the receiver. No outside antenna.
> 
> Ray
> 
> -------- Original Message --------
> Subject: Re: [time-nuts] WWVB Dephaser Question
> From: Bob kb8tq <kb8tq at n1k.org>
> Date: Thu, October 08, 2020 12:40 pm
> To: Discussion of precise time and frequency measurement
> <time-nuts at lists.febo.com>
> 
> Hi
> 
> A lot depends on your antenna setup. You can also swamp out the incoming
> WWVB signal…….
> 
> Bob
> 
>> On Oct 8, 2020, at 2:07 PM, <rcbuck at atcelectronics.com> <rcbuck at atcelectronics.com> wrote:
>> 
>> I have read several different articles where the WWVB phase shift is
>> eliminated by doubling the signal to 120 kHz. Several members of the
>> list have built these units.
>> 
>> Assume I build a circuit to double the incoming signal and use a schmitt
>> trigger to get a 120 kHz square wave. If I then divide that signal back
>> down to 60 kHz will that signal be strong enough to swamp out the WWVB
>> signal? I'm guessing it will be since it is at the 5 volt level and
>> somewhere in the +25 dBm or greater range.
>> 
>> Ray,
>> AB7HE
>> 
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