[time-nuts] 10 MHz -> 16 MHz

Dana Whitlow k8yumdoober at gmail.com
Sun Sep 30 04:18:33 EDT 2018


Tom,

Divide the 10 MHz down to 2 MHz in the usual way, then multiply by 8
with a cascade of three analog freq doublers separated by fairly narrow
bandpass filters.  Caveats:  Would need four filters total along the path
to get rid of unwanted frequency components, gain distributed along
the path to keep the signal level high enough to satisfy the doublers,
and might suffer excessive phase drift due to temperature changes of
the filters (and probably to a lesser extent) the doublers themselves.
You didn't mention phase stability requirements...

Freq doublers based on mixers or on full-wave rectification have the
pleasant property of having *most* of their output power in the proper
harmonic order, but require sinusoidal drives to work.  An unfiltered
digital drive signal won't suffice here.

Dana



On Sat, Sep 29, 2018 at 10:58 PM Tom Van Baak <tvb at leapsecond.com> wrote:

> What's a clever, simple, reliable (pick 2 of 3) way to get 16 MHz out of
> 10 MHz? Low phase noise isn't a big requirement and jitter doesn't need to
> be sub-nanosecond. The main requirement is perfect cycle count accuracy.
> This is for driving a 16 MHz microcontroller from a 10 MHz Rb/Cs/GPSDO. 10
> MHz input is likely sine; 16 MHz output is 3v3 or 5v CMOS.
>
> Thanks,
> /tvb
>
>
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